Need help with curve data 
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Amberftw
Posts: 11

Joined: 1/2/2009
Topic  Need help with curve data       Flag »  Reply »
This is for my homework. We are doing curve data right now. I was given 5 curves and only given bits and peices of info and I am to find out all other data. I have all curve data for curves 1,2, and 5. On curve 3 I am only given long chord and external secant. I know the formulas for long chord and external secant but I need a formula that has C and E and will give me delta or radius. Does anyone know the formula? I have also watched my teacher combine formulas by dividing them into one another but when I do it it doenst work out. Thanx so much for any inputs!
 Amber
  Saturday, February 21, 2009 at 8:51:54 PM
Thomas LaCorte
Posts: 62

Joined: 10/17/2008
Reply  Re: Need help with curve data Flag »  Reply »
Hi Amberftw, wow it has been a long time since I have used the formulas. I had them all written down on a crust old piece of parchment that I would carry before calculators went programable!! But good news! just look in the back of any field book and you will find the curve and reduction tables!! Dont have a blank field book? Go get one ASAP at any local survey shop. They are only a few bucks and are worth every penny for a student.....Tom
  Sunday, February 22, 2009 at 5:23:57 PM
Dave Lindell
Posts: 14
Location: Hacienda Heights, USA

Joined: 10/20/2008
Reply  Re: Need help with curve data Flag »  Reply »
Post what you have on the "Problem Corner" below and we'll see if we can help you.

Or e-mail them to me:DLLindell@msn.com.  I won't solve them, but I'll tell you how.
  Sunday, February 22, 2009 at 10:35:00 PM
Eagle
Posts: 4

Joined: 4/5/2009
Reply  Re: Need help with curve data Flag »  Reply »
DEGREE OF CURVE= 5729.58/R
TANGENT=RTAN(I/2) :I= INTERSECTION ANGLE BETWEEN TANGENT
L=R*I*PI/180           :PI=3.1416
LC=2*R*SIN(I/2)
M=R{1-COS(I/2)}
E=R{1/COS(I/2)-1}

GOOD LUCK
  Thursday, April 09, 2009 at 2:04:45 AM
Amberftw
Posts: 11

Joined: 1/2/2009
Reply  Re: Need help with curve data Flag »  Reply »
Sorry it took so long! I finally called my teacher and the way it was worded I thought he was talking about the external cecant but it was the tangent so after that it was a breeze. And if anyone else can use it I will post the curve data formulas. Also easy to derive from a sketch. Can show you how to do that but you would have to e-mail me from them norton_amber@live.com.

L= delta/360 * (2)(pie)(R)
T= (R) tan(delta/2)
C=2R sin(delta/2)
M=r (1-cos(delta/2))
E= r(1/cos(delta/2)-1)
DsubA also Degree of curve by Arc definition= 18000/(pie)R
DsubC also Degree of curve by Chord definition= 2 Arcsin(50/R)
Dsubf=DsubA/200=90/pieR=delta/2L
  Sunday, May 31, 2009 at 12:02:56 PM

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